x^2+28x-1156=0

Solution for x^2+28x-1156=0 equation:

x^2+28x-1156=0

a = 1; b = 28; c = -1156;
Δ = b2-4ac
Δ = 282-4·1·(-1156)
Δ = 5408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5408}=\sqrt{2704*2}=\sqrt{2704}*\sqrt{2}=52\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-52\sqrt{2}}{2*1}=\frac{-28-52\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+52\sqrt{2}}{2*1}=\frac{-28+52\sqrt{2}}{2}
$